The Ksp of PbI2 is 1.4 x 10-8. Calculate the molar solubility of PbI2 in 0.01...

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Chemistry

The Ksp of PbI2 is 1.4 x 10-8. Calculate the molar solubility ofPbI2 in 0.01 M NaI.

1.5 x 10-3 M
1.4 x 10-4 M
1.4 x 10-6 M
5.6 x 10-2 M

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3.8 Ratings (654 Votes)

answer : 1.4 x 10^-4 M

concentration of [I-] = 0.01 M

PbI2   <-------------> Pb+2   +   2 I-

                                  S             2S

                                  S            2S + 0.01

                                 S             0.01

Ksp = [Pb+2][I-]^2

1.4 x 10^-8 = S x (0.01)^2

S = 1.4 x 10^-4 M

solubility of PbI2 = 1.4 x 10^-4 M


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