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The intersection angle of a 6° simple horizontal curve is 65°25', and the PC is located...

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Civil Engineering

The intersection angle of a 6° simple horizontal curve is65°25', and the PC is located at station (238+14). Determine: thelength of the curve (L), the station of the PT, the deflectionangle for setting out the first point after the PC, and the chordlength for setting out the first point after the PC, the deflectionangle for setting out the last point before the PT, and the chordlength for setting out the last point before the PT. The length ofthe curve is:

-The station of the PT:

-The deflection angle for setting out the first point after thePC is:

-The chord length for setting out the first point after the PCis:

-The deflection angle for setting out the last point before thePT is:

-The chord length for setting out the last point before the PTis:

Answer & Explanation Solved by verified expert
3.8 Ratings (422 Votes)
iAssuming the lengths are in feetThusassuming arc definationR 5729586 95493 ftBy definationhere I 6525 2560    See Answer
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