The integrated rate laws for zero-, first-, and second-orderreaction may be arranged such that they resemble the equation for astraight line,y=mx+b.
| Order | Integrated Rate Law | Graph | Slope |
| 0 | [A]=−kt+[A]0 | [A] vs. t | −k |
| 1 | ln[A]=−kt+ln[A]0 | ln[A] vs. t | −k |
| 2 | 1[A]= kt+1[A]0 | 1[A] vs. t | k |
1) The reactant concentration in a zero-order reaction was6.00×10−2M after 150 sand3.50×10−2M after 330 s . What is the rateconstant for this reaction? Express your answer with theappropriate units.
2) What was the initial reactantconcentration for the reaction described in Part A?Express your answer with theappropriate units.
3) The reactant concentration ina first-order reaction was 9.20×10−2 M after 50.0s and 7.50×10−3 M after 60.0s . What is the rate constant for this reaction?Express your answer with theappropriate units.
4) The reactant concentration in a second-orderreaction was 0.440 Mafter 180 s and5.70×10−2 Mafter 860 s . What is the rateconstant for this reaction? Express your answer with the appropriate units.Include an asterisk to indicate a compound unit withmulitplication, for example write a Newton-meter asN*m.
