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The hydrolysis of 1-chloro-1-methyl cylcoheptane in 80% ethanol follows a first order rate equation. The values...

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Chemistry

The hydrolysis of 1-chloro-1-methyl cylcoheptane in 80% ethanolfollows a first order rate equation. The values of the specificreaction rate constants are:

temp/C0253545
k/s-11.06x10-53.19x10-49.86x10-42.92x10-3

1. Plot Ln(k) against 1/T

2. Calculate the activation energy

3. Calculate the pre-exponential factor

Answer & Explanation Solved by verified expert
4.3 Ratings (863 Votes)

K    = A e-Ea/RT

lnK   = lnK-Ea/RT

lnK = -Ea/RT +lnK

Y    = mx+C

Plot Ln(k) against 1/T. A straight line does not passed through origine.Negative slope4

logk2/K1   =   Ea/2.303R [1/T1 --1/T2]

log3.19*10-4/1.06*10-5   = Ea/2.303*8.314 [1/273 - 1/298]

1.4784*19.147                = Ea*(0.00366-0.003355)

   Ea                                   = 28.306/0.000305   = 92806.55Joules   = 92.80655KJ

3.K   = Ae-Ea/RT

1.06*10-5    = A e-92806.55/8.314*273

1.06*10-5       = Ae-40.88

1.06*10-5        = A*1.76*10-18

            A          = 1.06*10-5/1.76*10-18    = 6.02*1012 htz
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