The height (in meters) of a projectile shot vertically upward from a point 2 m...

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The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 21.5 m/s is h = 2 + 21.5t - 4.9t2 after t seconds.(a) Find the velocity (in m/s) after t seconds.v(t) = 1.9Find the velocity (in m/s) after 2 seconds and after 4 seconds.v(2) = 1.9m/sm/sV(4) = -17.7(b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height?v(t)m/s= 2.19When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.)S(c) What is the maximum height (in m)? (Round your answer to two decimal places.)25.58m(d) When (in s) does it hit the ground? (Round your answer to two decimal places.)S(e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.)m/s

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