The Grocery Manufacturers of America reported that 65% of consumers read the ingredients listed on a...

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The Grocery Manufacturers of America reported that 65% ofconsumers read the ingredients listed on a product's label. Assumethe population proportion is p=0.65 and a sample of 500 consumersis selected from the population.
(a) Show the sampling distribution of the sample proportion(p-bar) where, (p-bar) is the proportion of the sampled consumerswho read the ingredients listed on a product's label. (1) E(p)=(xxxx) (2 decimals) (2) std dev of (p-bar) = (xxxx)
(b) What is the probability that the sample proportion will bewithin .03 of the population proportion (to 4 decimals).
(c) . Answer part (b) for a sample of 600 (to 4 decimals).

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population proportion of consumers reading the ingredients listed on a products label is p065 sample size n 500 a From this sample proportion Ep population proportion p 065 Ep 065 sample variance p1pn 0651065500 065035500 02275500 See Answer

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