The gamma ray was fired with a Mev 7 energy, and it fell on a lead...

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The gamma ray was fired with a Mev 7 energy, and itfell on a lead barrier and stopped inside it behind the barrier.There was a gamma ray spectrometer. As a result of thisinteraction, the spectrometer did not record the 7 Mev energy, butrecorded a photovoltaic energy worth Kev 511. From these data,answer the questions.
A- What is the interaction between the photon and the leadbarrier?
B- What are the particles resulting from this reaction and what aretheir energies?
C- If the photon of the KeV 511 energy shed falls on a barrier ofthe bees, then what is the energy of the orbital electron K thatwill be released as a result of energy absorption Kev 511 if youknow that this electron is connected to a energy of KeV 8.98
D- If the photon with the energy Kev 511 is dispersed through anangle of 45 then how much will it be The dispersed powers ofenergy?

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AnsaGamma rays are forms of electromagnetic radiation thatoccur with higher energy levels than those displayed by ultravioletor visible light Lead barriersare excellent for imaging procedures using ionizingradiation such as fluoroscopy    See Answer
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