The formation constant of M(CN)6 4 is 2 50 1017, where M isa generi...

M2 added number of moles volume 013 1 013 M CN added 115 M M2 6CN M ....

The formation constant* of [M(CN)6]4â€“ is 2.50 Ã— 1017, where M is a generic metal. A...

Free

70.2K

Verified Solution

Question

Chemistry

The formation constant* of [M(CN)6]4â€“ is 2.50 Ã— 1017, where M isa generic metal. A 0.130-mole quantity of M(NO3)2 is added to aliter of 1.150 M NaCN solution. What is the concentration of M2ions at equilibrium?

Answer & Explanation Solved by verified expert

3.8 Ratings (389 Votes)

[M2+] added = number of moles / volume
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.13 / 1
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.13 M

[CN-] added = 1.15 M

M2+Â Â Â Â Â +Â Â Â Â Â Â Â 6CN-Â Â Â Â Â Â Â ---------> [M(CN)6]4â€“
0.13Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1.15Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â

Since Kf is very large, reaction will go to completion
From reaction, 1 mol of M2+ reacts with 6 mol og CN-

so, 0.13 mol of M2+ requires= 0.13*6 = 0.78 mol of CN-

So M2+ is limiting reagent and whole of M2+ will react

So,
there will not be any M2+ at equilibrium

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member