The formation constant* of [M(CN)4]2– is 7.70 × 1016, where M is a generic metal. A...

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The formation constant* of [M(CN)4]2– is 7.70 × 1016, where M isa generic metal. A 0.140-mole quantity of M(NO3)2 is added to aliter of 0.890 M NaCN solution. What is the concentration of M +2ions at equilibrium?

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1531016 M Explanation i Given moles of M2 0140 given moles of CN 0890mol1000ml 1000ml 0890mol ii Consider the formation of MCN42 is complete The reaction between M2 and CN    See Answer
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