The following statistics are calculated by sampling from four normal populations whose variances are equal: (You...

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The following statistics are calculated by sampling from fournormal populations whose variances are equal: (You may find ituseful to reference the t table and the q table.)
xÂ¯1 = 169, n1 = 5; xÂ¯2 = 179, n2 = 5; xÂ¯3 = 172, n3 = 5; xÂ¯4 =162, n4 = 5; MSE = 55.8
a. Use Fisherâ€™s LSD method to determine which population meansdiffer at Î± = 0.05. (Negative values should be indicated by a minussign. Round intermediate calculations to at least 4 decimal places.Round your answers to 2 decimal places.)
Population Mean DifferencesConfidence IntervalCan we concludethat the population means differ?Î¼1 âˆ’ Î¼2[,]Î¼1 âˆ’ Î¼3[,]Î¼1 âˆ’ Î¼4[,]Î¼2 âˆ’Î¼3[,]Î¼2 âˆ’ Î¼4[,]Î¼3 âˆ’ Î¼4[,]
b. Use Tukeyâ€™s HSD method to determine which population meansdiffer at Î± = 0.05. (If the exact value for nT â€“ c is not found inthe table, then round down. Negative values should be indicated bya minus sign. Round intermediate calculations to at least 4 decimalplaces. Round your answers to 2 decimal places.)
Population Mean DifferencesConfidence IntervalCan we concludethat the population means differ?Î¼1 âˆ’ Î¼2[,]Î¼1 âˆ’ Î¼3[,]Î¼1 âˆ’ Î¼4[,]Î¼2 âˆ’Î¼3[,]Î¼2 âˆ’ Î¼4[,]Î¼3 âˆ’ Î¼4[,]

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4.3 Ratings (785 Votes)

Here we have 4 groups and total number of observations are 20So degree of freedom isdf 204 16aCritical value of t for and df 16 is 21199 The Fishers LSD Value isSo confidence intervals areFor Since confidence interval contains zero so we cannot concludethat populaiton means See Answer

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