The following reaction was performed in a sealed vessel at 724*C : H2(g)+I2(g)?2HI(g) Initially, only H2 and I2...

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Chemistry

The following reaction was performed in a sealed vessel at 724*C:
H2(g)+I2(g)?2HI(g)
Initially, only H2 and I2 were present at concentrations of[H2]=3.85M and [I2]=2.85M. The equilibrium concentration of I2 is0.0800M . What is the equilibrium constant, Kc, for the reaction atthis temperature?
Express answer numerically

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4.1 Ratings (520 Votes)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â H2(g)+Â Â Â Â Â I2(g)Â Â Â Â Â <--->Â Â Â Â 2HI(g)
initial:Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3.85Â Â Â Â Â Â Â Â Â Â 2.85Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0
at equlibrium:Â Â Â Â Â Â 3.85-xÂ Â Â Â Â Â Â Â Â 2.85-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2x

given at equilibrium, [I2]=0.08 M
so,
2.85-x = 0.08
x= 2.77 M

[H2]= 3.85-x = 3.85 - 2.77 = 1.08 M

[HI]= 2x = 2* 2.77=5.54 M

Kc = [HI]^2/{[H2]*[I2]}
Â Â = 5.54^2 / (1.08*0.08)
Â Â =355.23

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