The first dilution with me 1/100th of the originalconcentration. In other words, one hundreth part of the secondsolution will be dye and 99 parts will be water. Te final volume ofthe solution will be 10ml.
a) what part of it will be dye?
b) what part of it will be water?
the second dilution will be 1/10th of the first dilution. Thefinal volume will be 10ml.
a) therefore, how many ml of water do you place in secondtube
b) how many ml of the first dilution tube do you add
the third dilution will the 1/10th of the second one. again, thefinal volume will be 10 ml.
a) therefore, how many ml of water do you place in secondtube?
b) how many ml of the second dilution tube do you add?
Edit question
finally, the fourth dilution will be 1/100th of the third one.again, the final volume will be 10 ml.
a) therefore, how many ml of water do you place in the secondtube?
b) how many ml of the third dilution tube do you add?
How do you calculate the final dilution factor in this series?Double check that it contains 10^-6 parts dye to water in the finalsolution.
