The equilibrium constant, Kc, for the following reaction is 1.05Ã—10-3 at 446 K. PCl5(g) PCl3(g) +...

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The equilibrium constant, Kc, for the following reaction is1.05Ã—10-3 at 446 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficientlylarge sample of PCl5(g) is introduced into an evacuated vessel at446 K, the equilibrium concentration of Cl2(g) is found to be 0.498M. Calculate the concentration of PCl5 in the equilibrium mixture.M_A student ran the following reaction in the laboratory at 689 K:N2(g) + 3H2(g) 2NH3(g) When she introduced 4.06Ã—10-2 moles of N2(g)and 5.20Ã—10-2 moles of H2(g) into a 1.00 liter container, she foundthe equilibrium concentration of H2(g) to be 5.00Ã—10-2 M. Calculatethe equilibrium constant, Kc, she obtained for this reaction. Kc =_____________________A student ran the following reaction in the laboratory at 658 K:2NH3(g) N2(g) + 3H2(g) When she introduced 8.28Ã—10-2 moles ofNH3(g) into a 1.00 liter container, she found the equilibriumconcentration of NH3(g) to be 6.82Ã—10-3 M. Calculate theequilibrium constant, Kc, she obtained for this reaction. Kc =

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Question 1 The equilibrium constant Kc for the following reaction is 105103 at 446 K PCl5g PCl3g Cl2g When a sufficiently large sample of PCl5g is introduced into an evacuated vessel at 446 K the equilibrium concentration of Cl2g is found to be 0498 M Calculate the concentration of PCl5 in the equilibrium mixture M The Kc expression Kc See Answer

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