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The equilibrium constant in terms of pressures for the reduction of tungsten(IV) oxide to tungsten at 25...

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Chemistry


The equilibrium constant in terms of pressures for the reduction oftungsten(IV) oxide to tungsten at25 °C is Kp = 3.82×10-4,corresponding to the reaction

  • WO2(s) +2CO(g) = (doublearrow) W(s) +2CO2(g)

If the total pressure of an equilibrium system at 25 °C is2.67 atm, calculate the partial pressures ofCO(g) andCO2(g).

PCO =  atm

PCO2 =  atm

Answer & Explanation Solved by verified expert
3.9 Ratings (450 Votes)
Few things we have to remember in this type of problems Thetotal pressure given in the problem is the sum of    See Answer
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