The energy needed for the following process is 1.960 × 104 kJ/mol: Li(g) → Li3+(g) + 3e− If...

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Chemistry

The energy needed for the following process is 1.960 × 104kJ/mol:

Li(g) → Li3+(g) + 3e−

If the first ionization energy of lithium is 5.20 × 102 kJ/mol,calculate the second ionization energy of lithium—that is, theenergy required for the process:

Li+(g) → Li2+(g) + e−

A hydrogen-like ion is an ion containing only one electron. Theenergies of the electron in a hydrogen-like ion are given by

En = −(2.18 × 10−18 J) (Z2)(1/n2)

where En is the energy of the electron in the hydrogen-like ion,n is the principal quantum number, and Z is the atomic number ofthe element.

Second ionization energy of lithium:   kJ/mol (Enteryour answer in scientific notation)

Answer & Explanation Solved by verified expert
3.9 Ratings (793 Votes)
The energy needed to remove 3 electrons from Li atom given bythe following equation is Note that we can write the above process as a step wise gradualremoval of electrons one by one as followsStep 1This is the equation for    See Answer
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