The dibasic compound B (pKb1 = 4.03, pKb2 = 8.06) was titrated with 1.18 M HCl....

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The dibasic compound B (pKb1 = 4.03, pKb2 = 8.06) was titrated with1.18 M HCl. The initial solution of B was 0.118 M and had a volumeof 100.0 mL. Find the pH at the following volumes of acid added: Va= 0.00, 2.00, 5.00, 9.00, 10.00, 11.00, 15.00, 19.00, 20.00, and22.00 mL. (Assume Kw = 1.01 ✕ 10−14.)

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dibasic base pKb1 403 pKb2 806 millimoles of base 100 x 0118 118 a before addition of any HCl pOH 12 pKb1 logC pOH 12 pKb1 log 0118 12 403 log 0118 248 pH    See Answer
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