1.
mass of oxygen liquid = D*V
                     Â
= 1.14*2 = 2.28 Kg
DHvapourisation = 213 Kj/kg
Amount of heat absorbed = DHvap * m
                      Â
= 213*2.28
                     Â
= 485.64*10^3 joule.
2.
Water's heat of fusion = 80. cal/g
specific heat = 1.0 cal/g⋅∘C .
mass of water = 1400 grams
Heat absorbed (q) = 1400*1*(32-0)+1400*80 = 156800
cal
           Â
= 1.6*10^5 cal
3.
Water heat of fusion = 80. cal/g
specific heat = 1.0 cal/g⋅∘C .
water heat of vaporization = 540 cal/g
Heat absorbed (q) = mice*DHfus + mwater*s*DT +
m*DHvap
 Â
           Â
= 390*80 + (390+100)*1*(100-0)+490*540
           Â
= 3.4*10^5 cal