The decomposition of XY is second order in XYand has a rate constant of 6.92Ã—10âˆ’3 Mâˆ’1â‹…sâˆ’1at...

60.1K

Verified Solution

Question

Chemistry

The decomposition of XY is second order in XYand has a rateconstant of 6.92Ã—10^âˆ’3 Mâˆ’1â‹…sâˆ’1at a certaintemperature.
Part A
What is the half-life for this reaction at an initialconcentration of 0.100 M?
t1/2 =
.0125
Â Â sÂ Â
Part B
How long will it take for the concentration of XY to decrease to12.5% of its initial concentration when the initial concentrationis 0.100 M?
t = Â Â sÂ Â
Part C
How long will it take for the concentration of XY to decrease to12.5% of its initial concentration when the initial concentrationis 0.200 M?
t = ____ sÂ Â
Part D
If the initial concentration of XY is 0.160 M , how long will ittake for the concentration to decrease to 6.80Ã—10^âˆ’2 M?
Express your answer using two significant figures.
t = _ Â Â sÂ Â
Part E
If the initial concentration of XY is 0.050 M, what is theconcentration of XY after 55.0 s ?
Express your answer using two significant figures.
[XY]t = Â Â MÂ Â
Part F
If the initial concentration of XY is 0.050 M, what is theconcentration of XY after 600 s ?
Express your answer using two significant figures.
[XY]t = ___ Â Â MÂ Â
Please explain and show work with the answers, I have beenstruggling for the past hour trying to solve the problem!!! Thanksfor your help

Answer & Explanation Solved by verified expert

4.3 Ratings (726 Votes)

aWe know that for second order reaction the half life willbePart BHow long will it take for the concentration of XY to decrease to125 of its initial concentration when the initial See Answer

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member