2HCl + Na2CO3 ----> 2NaCl + CO2 +H2O
no of moles of Na2CO3 = weight of substance/Gram molecular
weight
                                   Â
= 0.8647/105.9891
                                    Â
= 0.00815 moles
From balanced equation
1 mole of Na2CO3 react with 2moles of HCl
0.00815 moles of Na2CO3 react with = 2*0.00815 =0.0163 moles of
HCl
Molarity     = no of moles*1000/volume
in ml
                Â
= 0.0163*1000/42.4
                Â
= 0.3844±0.0006M
molarity = 0.3844±0.0006M
                      Â