The average “moviegoer” sees 8.5 movies a year. A moviegoer isdefined as a person who sees at least one movie in a theater in a12-month period. A random sample of 40 moviegoers from a largeuniversity revealed that the average number of movies seen perperson was 9.6. The population standard deviation is 3.2 movies. Atthe 0.05 level of significance, can it be concluded that thisrepresents a difference from the national average?

STEP 1. State the null and alternate hypothesis

The hypotheses are  (Enter an UPPER CASE LetterOnly.)

STEP 2. State the critical value(s). Enter the appropriateletter.

z =

STEP 3. Calculate the test value

z =

STEP 4. Make the decision by rejecting or not rejecting the nullhypothesis. Since the test value falls in the non-rejection region,we do not reject the null hypothesis.

Conclusion 1. Reject the null hypothesis. At the α = 0.05significance level there is enough evidence to conclude that theaverage number of movies seen by people each year is not differentfrom 8.5.

Conclusion 2. Reject the null hypothesis. At the α = 0.05significance level there is enough evidence to conclude that theaverage number of movies seen by people each year is different from8.5.

Conclusion 3. Do not reject the null hypothesis. At the α = 0.05significance level there is enough evidence to conclude that theaverage number of movies seen by people each year is different from8.5.

Conclusion 4. Do not reject the null hypothesis. At the α = 0.05significance level there is enough evidence to conclude that theaverage number of movies seen by people each year is 8.5.

(Enter a number only from the list 1, 2, 3, or 4)