The age distribution of the Canadian population and the age distribution of a random sample of...

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The age distribution of the Canadian population and the agedistribution of a random sample of 455 residents in the Indiancommunity of a village are shown below.

Age (years)Percent of Canadian PopulationObserved Number
in the Village
Under 57.2%                  47            
5 to 1413.6%                  73            
15 to 6467.1%                  295            
65 and older12.1%                  40            

Use a 5% level of significance to test the claim that the agedistribution of the general Canadian population fits the agedistribution of the residents of Red Lake Village.

(a) What is the level of significance?


State the null and alternate hypotheses.

H0: The distributions are the same.
H1: The distributions are thesame.H0: The distributions are different.
H1: The distributions aredifferent.    H0: Thedistributions are the same.
H1: The distributions aredifferent.H0: The distributions aredifferent.
H1: The distributions are the same.


(b) Find the value of the chi-square statistic for the sample.(Round your answer to three decimal places.)


Are all the expected frequencies greater than 5?

YesNo    


What sampling distribution will you use?

uniformbinomial    chi-squarenormalStudent'st


What are the degrees of freedom?


(c) Estimate the P-value of the sample test statistic.

P-value > 0.1000.050 < P-value <0.100    0.025 < P-value <0.0500.010 < P-value < 0.0250.005 <P-value < 0.010P-value < 0.005


(d) Based on your answers in parts (a) to (c), will you reject orfail to reject the null hypothesis that the population fits thespecified distribution of categories?

Since the P-value > α, we fail to rejectthe null hypothesis.Since the P-value > α, wereject the null hypothesis.    Since theP-value ≤ α, we reject the null hypothesis.Sincethe P-value ≤ α, we fail to reject the nullhypothesis.


(e) Interpret your conclusion in the context of theapplication.

At the 5% level of significance, the evidence is insufficient toconclude that the village population does not fit the generalCanadian population.At the 5% level of significance, the evidenceis sufficient to conclude that the village population does not fitthe general Canadian population.    

Answer & Explanation Solved by verified expert
4.5 Ratings (636 Votes)

a) level of significance =0.05

H0: The distributions are the same.
H1: The distributions are different

b)

applying chi square test:

           relative observed Expected residual Chi square
category frequency Oi Ei=total*p R2i=(Oi-Ei)/√Ei R2i=(Oi-Ei)2/Ei
1 0.072 47 32.76 2.49 6.190
2 0.136 73 61.88 1.41 1.998
3 0.671 295 305.31 -0.59 0.348
4 0.121 40 55.06 -2.03 4.117
total 1.000 455 455 12.653

value of the chi-square statistic =12.653

Are all the expected frequencies greater than 5? :Yes

What sampling distribution will you use? Chi square

degree of freedom =categories-1= 3

c)

0.005 <P-value < 0.010

d)

Since the P-value ≤ α, we reject the null hypothesis.

e)

At the 5% level of significance, the evidence is sufficient to conclude that the village population does not fit the general Canadian population.    


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