The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3Ã—10âˆ’5. A. Calculate the equilibrium concentration of H3O+ in...

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The acid-dissociation constant for benzoic acid (C6H5COOH) is6.3Ã—10âˆ’5.
A. Calculate the equilibrium concentration of H3O+ in thesolution if the initial concentration of C6H5COOH is5.1Ã—10^âˆ’2M
B. Calculate the equilibrium concentration of C6H5COOâˆ’ in thesolution if the initial concentration of C6H5COOH is5.1Ã—10^âˆ’2 M .
C. Calculate the equilibrium concentration of C6H5COOH in thesolution if the initial concentration of C6H5COOH is5.1Ã—10^âˆ’2 M .

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Â Â Â Â Â Â Â Â Â Â Â Â Â C6H5COOH (aq) + H2O(l) ---------------> C6H5COO^- (aq) + H3O^+ (aq)

IÂ Â Â Â Â Â Â Â Â Â Â Â Â 5.1*10^-2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0

CÂ Â Â Â Â Â Â Â Â Â Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +x

EÂ Â Â Â Â Â Â Â Â Â Â 5.1*10^-2 -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +x

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â KaÂ Â Â Â Â =Â Â Â [C6H5COO^-][H3O^+]/[C6H5COOH]

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.3*10^-5Â Â = x*x/(5.1*10^-2-x)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.3*10^-5 *(5.1*10^-2 -x)Â Â = x^2

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â xÂ Â Â = 0.00176

A.Â Â [H3O^+]Â Â Â = xÂ Â Â = 0.00176M

B.Â Â [C6H5COO^-]Â Â Â = xÂ Â Â = 0.00176M

C.Â Â [C6H5COOH]Â Â Â = 5.1*10^-2 - xÂ Â Â Â = 5.1*10^-2 -0.00176Â Â = 0.04924M

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The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3Ã—10âˆ’5. A. Calculate the equilibrium concentration of H3O+ in...

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