Suppose you have a bag of 100 coins. Ninety of them are fair coins, which is...

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Suppose you have a bag of 100 coins. Ninety of them are faircoins, which is P(H) = P(T) = 1/2. The other 10 coins are biased ,they have tail (T) on both sides. Let X = {X1, X2, · · · , X100} bea random variable denoting the the total number of heads in the 100coin flips.

a. How many possible values X can take? For example, if onetosses two fair coins, the number of total heads could be 0, 1,2.

b. How many ways the value of X could be 1?

c. How many ways the value of X could be 2?

d. How many ways the value of X could be 25?

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Ans Ninety of them are fair coins which is PH PT 12 10 coins are biased they have tail T on both sides Xi denote the total number of heads in ith    See Answer
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