Suppose we have a solution of lead nitrate, Pb(NO3)2(aq). A
solution of NaCl(aq) is added slowly...
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Suppose we have a solution of lead nitrate, Pb(NO3)2(aq). Asolution of NaCl(aq) is added slowly until no further precipitationoccurs. The precipitate is collected by filtration, dried, andweighed. A total of 11.72 g of PbCl2(s) is obtained from 200.0 mLof the original solution. Calculate the molarity of thePb(NO3)2(aq) solution.
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Given that 1172 g of PbCl2s is obtained from 2000 mL of the original solution of PbNO32aq Mass of PbCl2s 1172 g Molar mass of PbCl2s
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