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Suppose that we have two masses, m1 and m2, traveling at initial velocities v1i and v2i...

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Physics

Suppose that we have two masses, m1 and m2, traveling at initialvelocities v1i and v2i . After they collide, they will havevelocities v1f and v2f . The collision will happen along a straightline, and there are no external forces involved.

Exercise 1 Let m1 = 0.20 kg, m2 = 0.50 kg, v1i = 0.50 m/s, andv2i = 0.0 m/s. If v2f = 0.286 m/s, what is v1f ?

For the collision above what are the initial and final kineticenergies? Is kinetic energy conserved in the collision?

Let m1 = 500 g, m2 = 500 g, v1i = 0.45 m/s, and v2i = 0.0 m/s.If v1f = 0.225 m/s, what is v2f ? Simply stated, what would you sayabout the two masses after the collision? What type of collision isthis?

Answer & Explanation Solved by verified expert
4.0 Ratings (789 Votes)

1.

By Conservation of momentum

M1V1i + M2V2i = M1V1f+ M2V2f

0.2*0.5+0.5*0 = 0.2*V1f +0.5*0.286

V1f = -0.215 m/s

Initial Kinetic energy is

Kinitial = (1/2)M1V1i2 +(1/2)M2V2i2 =(1/2)(0.2)(0.5)2 +(1/2)(0.5)(0)2=0.025 J

Final Kinetic energy is

Kfinal= (1/2)M1V1f2 +(1/2)M2V2f2 =(1/2)(0.2)(-0.215)2 +(1/2)(0.5)(0.286)2=0.025 J

Since Kinitial = Kfinal ,KInetic energy is conserved

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2.

By Conservation of momentum

M1V1i + M2V2i = M1V1f+ M2V2f

0.5*0.45+0.5*0 = 0.5*0.225+0.5*V2f

V2f = 0.225 m/s

After the collision the masses move with the same velocity in same direction.

Initial Kinetic energy is

Kinitial = (1/2)M1V1i2 +(1/2)M2V2i2 =(1/2)(0.5)(0.45)2 +(1/2)(0.5)(0)2=0.050625 J

Final Kinetic energy is

Kfinal= (1/2)M1V1f2 +(1/2)M2V2f2 =(1/2)(0.5)(0.225)2 +(1/2)(0.5)(0.226)2=0.0253125 J

Since initial kinetic energy Kinitial is not equal to final kinetic energy Kfinal.The Collision is Inelastic
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