Suppose 31 pregnant women are sampled who smoke an average of 22 cigarettes per day with...

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Suppose 31 pregnant women are sampled who smoke an average of 22cigarettes per day with a variance of 144.00.

a) What is the probability that the pregnant women will smoke anaverage of 20 cigarettes or more? probability =

b) What is the probability that the pregnant women will smoke anaverage of 21 cigarettes or less? probability =

c) What is the probability that the pregnant women will smoke anaverage of 18 to 24 cigarettes? probability =

d) What is the probability that the pregnant women will smoke anaverage of 23 to 26 cigarettes? probability =

Note: Do NOT input probability responses as percentages; e.g.,do NOT input 0.9194 as 91.94.

Answer & Explanation Solved by verified expert
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Solution Given that mean 22variance 2 14400standard deviation 2 14400 12n    See Answer
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