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  1. mathematics
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  3. solve by determinants a.x+y+z=0 3x-y+2z=-1 2x+3y+3

solve by determinants a.x+y+z=0 3x-y+2z=-1 2x+3y+3z=-5 b. x+2z=1 2x-3y=3 y+z=1 c. x+y+z=10 3x-y=0 3y-2z=-3 d. -8x+5z=-19 -7x+5y=4 -2y+3z=3 e. -x+2y+z-5=0 3x-y-z+7=0 -2x+4y+2z-10=0 f. 1/x+1/y+1/z=12 4/x-3/y=0 2/y-1/z=3

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Verified Solution

Question

Basic Math

solve by determinants

a.x+y+z=0

3x-y+2z=-1

2x+3y+3z=-5

b. x+2z=1

2x-3y=3

y+z=1

c. x+y+z=10

3x-y=0

3y-2z=-3

d. -8x+5z=-19

-7x+5y=4

-2y+3z=3

e. -x+2y+z-5=0

3x-y-z+7=0

-2x+4y+2z-10=0

f. 1/x+1/y+1/z=12

4/x-3/y=0

2/y-1/z=3

Answer & Explanation Solved by verified expert
4.2 Ratings (876 Votes)
a Given xyz 03xy2z 12x3y3z 5Here the coefficient matrix is A Then D detA 3Therefore there exists a unique a solution for xyzNow Dx 15Dy 6Dz 21Therefore x DxD 153 5y DyD 63 2z DzD 213 7Hence the solution is x 5 y 2 z 7b Given x2z    See Answer
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