Sodium fluoride is added to many municipal water supplies to reduce tooth decay. Calculate the pH...

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Chemistry

Sodium fluoride is added to many municipal water supplies toreduce tooth decay. Calculate the pH of a 0.00307 M solution ofNaF, given that the Ka of HF= 6.80 x 10-4 at25 degree celcius.

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4.4 Ratings (724 Votes)

                 NaF -------> Na+   + F-

               0.00307M                0.00307M

             F- + H2O --------> HF + OH-

I           0.00307                  0       0

C           -x                          +x     +x

E        0.00307-x                +x     +x

Kb   = Kw/Ka

          = 1*10-14/6.8*10-4

            = 1.47*10-11

     Kb   = [HF]{OH-]/[HF]

      1.47*10-11    = x*x/0.00307-x

    1.47*10-11 *(0.00307-x) = x2

           x = 2.12*10-7

      [OH-]   = x   = 2.12*10-7 M

     POH   = -log[OH-]

                = -log2.12*10-7

                = 6.6736

      PH    = 14-POH

               = 14-6.6736   = 7.3264


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