a)
Ho: there is no relationship between two given two variables
Ha: there is a relationship between two given two variables
b)
Chi-Square Test of independence |
Observed Frequencies |
|
0 |
|
0 |
1 |
2 |
3 |
4 |
Total |
male |
17 |
16 |
7 |
5 |
45 |
female |
10 |
9 |
17 |
14 |
50 |
|
|
|
|
|
|
Total |
27 |
25 |
24 |
19 |
95 |
|
|
|
|
|
|
|
Expected frequency of a cell = sum
of row*sum of column / total sum |
|
Expected Frequencies |
|
1 |
2 |
3 |
4 |
Total |
male |
27*45/95=12.789 |
25*45/95=11.842 |
24*45/95=11.368 |
19*45/95=9 |
45 |
female |
27*50/95=14.211 |
25*50/95=13.158 |
24*50/95=12.632 |
19*50/95=10 |
50 |
|
|
|
|
|
|
Total |
27 |
25 |
24 |
19 |
95 |
|
|
|
|
|
|
|
(fo-fe)^2/fe |
|
male |
1.3862 |
1.4599 |
1.679 |
1.778 |
|
female |
1.2476 |
1.3139 |
1.511 |
1.600 |
|
c)
Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe
=Â Â 11.9747
  Number of Rows =  2
Number of Columns =Â Â 4
Degrees of Freedom=(#row - 1)(#column -1) = (2- 1 ) * ( 4- 1 )
=Â Â 3
 Â
p-Value =Â Â 0.0074705
d)
Decision:   p-value < α , Reject
Ho Â
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