Sally chemist is attempting to determine the mass % of acetic acid in vinegar. Below is...

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Chemistry

Sally chemist is attempting to determine the mass % of aceticacid in vinegar. Below is an excerpt from her lab book:
A. Prepared vinegar analyte
25.0 mL vinegar
mass of vinegar 25.20 grams
added 75.0 mL H₂O
added 2 drops phenolphthalein
temperature: 27.0 ^oC
manufacturer's mass % acetic acid = 3.5 %
B. Prepared burette
filled with standardized NaOH solution 0.201 M
C. Titration
initial burette reading: 5.12 mL
final burette reading: 78.67 mL
solution is light pink
1. What is the density of her vinegar samlpe?
2. Use the manufacturers reported mass % acetic acid to estimatehow many moles of acetic acid are present in her analyte.
3. Use your result from 2 to estimate how many mL ofstandardized NaOH solution she will need to reach the equivalencepoint.
4. Use Sally's data to calculate the molarity of acetic acid inher vinegar sample.
5 Use the results from 4 to calculate the mass % of acetic acidin Sally's vinegar sample.

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3.7 Ratings (455 Votes)

1CALCULATION OF DENSITY OF VINEGAR SAMPLE Density MassVolume Mass of Vinegar 2520 g Volume of vinegar 250 mL Density of vinegar MassVolume 2520 g250 mL 1008 gmL 2 CALCULATION OF NUMBER OF MOLES OF ACETIC ACID IN THE ANALYTE Mass of acetic acid 35 That means 100 g of vinegar contains 35 g of acetic acid Therefore 2502g of vinegar contains 35 g x 2502g 100g of acetic acid 08757 g of acetic acid We have to calculate the number of moles corresponding to 08757 g of acetic acid Number of See Answer

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