Recall that Benford's Law claims that numbers chosen from very large data files tend to have...

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Statistics

Recall that Benford's Law claims that numbers chosen from verylarge data files tend to have \"1\" as the first nonzero digitdisproportionately often. In fact, research has shown that if yourandomly draw a number from a very large data file, the probabilityof getting a number with \"1\" as the leading digit is about 0.301.Now suppose you are the auditor for a very large corporation. Therevenue file contains millions of numbers in a large computer databank. You draw a random sample of n = 229 numbers fromthis file and r = 88 have a first nonzero digit of 1. Letp represent the population proportion of all numbers inthe computer file that have a leading digit of 1.

(i) Test the claim that p is more than 0.301. Useα = 0.05.

(a) What is the level of significance?


State the null and alternate hypotheses.

H0: p = 0.301;H1: p < 0.301

H0: p > 0.301;H1: p = 0.301  

   H0: p = 0.301;H1: p ≠ 0.301

H0: p = 0.301;H1: p > 0.301


(b) What sampling distribution will you use?

The standard normal, since np < 5 and nq< 5.

The Student's t, since np < 5 andnq < 5.

     The standard normal, since np> 5 and nq > 5.

The Student's t, since np > 5 andnq > 5.


What is the value of the sample test statistic? (Round your answerto two decimal places.)


(c) Find the P-value of the test statistic. (Round youranswer to four decimal places.)

(d) Based on your answers in parts (a) to (c), will you rejector fail to reject the null hypothesis? Are the data statisticallysignificant at level α?

At the α = 0.05 level, we reject the null hypothesisand conclude the data are statistically significant.

At the α = 0.05 level, we reject the null hypothesisand conclude the data are not statistically significant.

    At the α = 0.05 level, we fail toreject the null hypothesis and conclude the data are statisticallysignificant.

At the α = 0.05 level, we fail to reject the nullhypothesis and conclude the data are not statisticallysignificant.


(e) Interpret your conclusion in the context of theapplication.

There is sufficient evidence at the 0.05 level to conclude thatthe true proportion of numbers with a leading 1 in the revenue fileis greater than 0.301.

There is insufficient evidence at the 0.05 level to concludethat the true proportion of numbers with a leading 1 in the revenuefile is greater than 0.301.    


(ii) If p is in fact larger than 0.301, it would seemthere are too many numbers in the file with leading 1's. Could thisindicate that the books have been \"cooked\" by artificially loweringnumbers in the file? Comment from the point of view of the InternalRevenue Service. Comment from the perspective of the Federal Bureauof Investigation as it looks for \"profit skimming\" by unscrupulousemployees.

No. There does not seem to be too many entries with a leadingdigit 1.

Yes. There seems to be too many entries with a leading digit1.

    No. There seems to be too many entries with aleading digit 1.

Yes. There does not seem to be too many entries with a leadingdigit 1.


(iii) Comment on the following statement: If we reject the nullhypothesis at level of significance α , we have not provedH0 to be false. We can say that the probabilityis α that we made a mistake in rejectingHo. Based on the outcome of the test, would yourecommend further investigation before accusing the company offraud?

We have not proved H0 to be false. Becauseour data lead us to accept the null hypothesis, more investigationis not merited.

We have not proved H0 to be false. Becauseour data lead us to reject the null hypothesis, more investigationis not merited.

    We have proved H0 to befalse. Because our data lead us to reject the null hypothesis, moreinvestigation is not merited.

We have not proved H0 to be false. Becauseour data lead us to reject the null hypothesis, more investigationis merited.

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We would be looking first question i all 5 parts here asi a The level of significance is given in the problem as005 Therefore 005 is the level of significancehereAs we are testing here whether p is more than 0301therefore the    See Answer
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