Real Fruit Juice: A 32 ounce can of a popular fruit drink claimsto contain 20% real fruit juice. Since this is a 32 ounce can, theyare actually claiming that the can contains 6.4 ounces of realfruit juice. The consumer protection agency samples 44 such cans ofthis fruit drink. Of these, the mean volume of fruit juice is 6.33with standard deviation of 0.19. Test the claim that the meanamount of real fruit juice in all 32 ounce cans is 6.4 ounces. Testthis claim at the 0.05 significance level.

(a) What type of test is this?

This is a left-tailed test.

This is a right-tailed test.

This is a two-tailed test.

(b) What is the test statistic? Round your answer to 2 decimalplaces.

t x =

(c) Use software to get the P-value of the test statistic. Roundto 4 decimal places.

P-value =

(d) What is the conclusion regarding the null hypothesis?

reject H0

fail to reject H0

(e) Choose the appropriate concluding statement.

There is enough data to justify rejection of the claim that themean amount of real fruit juice in all 32 ounce cans is 6.4ounces.

There is not enough data to justify rejection of the claim thatthe mean amount of real fruit juice in all 32 ounce cans is 6.4ounces.

We have proven that the mean amount of real fruit juice in all32 ounce cans is 6.4 ounces.

We have proven that the mean amount of real fruit juice in all32 ounce cans is not 6.4 ounces.