QUESTION 1 Calculate the mass of SO3 formed when 9.42 g of SO2 reacts with 4.50 g...

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Chemistry

QUESTION 1

Calculate the mass of SO3 formed when 9.42 g ofSO2 reacts with 4.50 g of O2 according to thefollowing reaction.

                      2SO2+ O2 → 2SO3

a.

22.52 g

b.

11.77 g

c.

11.25 g

d.

34.27 g

e.

5.63 g

QUESTION 2

If 12.002g of potassium oxalate hydrate is added to a beaker andthen 20mL of DI water is added to dissolve and then 8.0mL of 1.5 MFeCl3 is added. Which statement is correct

a.

the beaker contains 0.173 moles of potassium oxalate hydrate and0.012 moles of iron(III) chloride

b.

the beaker contains 0.0651 moles of potassium oxalate hydrateand 0.012 moles of iron(III) chloride

c.

the beaker contains 3.255 moles of potassium oxalate hydrate and0.012 moles of iron(III) chloride

d.

the beaker contains 0.012 moles of potassium oxalate hydrate and0.0651 moles of iron(III) chloride

e.

the beaker contains 3.255 moles of potassium oxalate hydrate and12.0 moles of iron(III) chloride

QUESTION 3

The reaction of 35.0 g of Al with excess g ofCr2O3 produced 25.6 g of Cr. What is thepercent yield for this reaction?

                      2Al+ Cr2O3 → Al2O3 +2Cr

a.

51.0%

b.

196.3%

c.

73.1%

d.

75.9%

e.

37.9%

QUESTION 4

Chlorine gas can be made from the reaction of manganese dioxidewith hydrochloric acid.

                      MnO2(s)+ 4HCl(aq) → MnCl2(aq) + 2H2O(l) +Cl2(g)

            Accordingto the above reaction.

If 1.5 moles of MnO2 are reacted with 5.6 moles ofHCl which of the following statements is true?

a.

HCl is the limiting reactant and 11.2 mol of water isproduced

b.

HCl is the limiting reactant and 2.8 mol of water isproduced

c.

MnO2 is the limiting reactant and 3.0 mol of water isproduced

d.

HCl is the limiting reactant and 5.8 mol of water isproduced

e.

MnO2 is the limiting reactant and 5.8 mol of water isproduced

Answer & Explanation Solved by verified expert
3.8 Ratings (508 Votes)
Question 1 The reaction is SO2 12 O2 SO3 Mass of SO2 942 g molar mass of SO2 64 gmol moles of SO2 massmolar mass 94264 0147 mol Mass of O2 450 g molar mass of O2 32 gmol moles of O2 massmolar mass 45032 0141 mol In reaction for 1 mole of SO2 05 mol of O2 is used So for 0147 mol of SO2 moles of O2 used 050147 0074 mol So O2 is in excess in    See Answer
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