Q11. Use the given information to find the number of degrees ofâ€‹ freedom, the critical values chi...

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Q11. Use the given information to find the number of degrees ofâ€‹freedom, the critical values
chi Subscript Upper L Superscript 2Ï‡2L
and
chi Subscript Upper R Superscript 2Ï‡2Râ€‹,
and the confidence interval estimate of
sigmaÏƒ.
It is reasonable to assume that a simple random sample has beenselected from a population with a normal distribution.
Platelet Counts of Women
90â€‹%
â€‹confidence;
n=40â€‹,
s=65.5.
The confidence interval estimate of sigmaÏƒ is:
_____less than
â€‹(Round to one decimal place asâ€‹ needed.)

Answer & Explanation Solved by verified expert

3.8 Ratings (415 Votes)

Sample Size,Â Â n=Â Â 40Â Â
Sample Standard Deviation,Â Â s=Â Â 65.5000Â Â
Confidence Level,Â Â CL=Â Â 0.90Â Â
Â Â Â Â Â Â Â Â
Â Â Â Â Â Â Â Â
Degrees of Freedom,Â Â DF=n-1 = Â Â 39Â Â
alpha,Â Â Î±=1-CL=Â Â 0.1Â Â
alpha/2 ,Â Â Î±/2=Â Â 0.05Â Â
Lower Chi-Square Value=Â Â Ï‡Â²_1-Î±/2 =Â Â 25.6954Â Â
Upper Chi-Square Value=Â Â Ï‡Â²_Î±/2 =Â Â 54.5722Â Â
Â Â Â Â Â Â Â Â
confidence interval for variance isÂ Â Â Â Â Â Â Â
lower bound=Â Â (n-1)sÂ²/Ï‡Â²_Î±/2 =Â Â 3066.02Â Â
Â Â Â Â Â Â Â Â
Â Â Â Â Â Â Â Â
upper bound=Â Â (n-1)sÂ²/Ï‡Â²_1-Î±/2 =Â Â 6511.66Â Â
Â Â Â Â Â Â Â Â

Â Â Â Â Â
confidence interval for std dev is Â Â Â Â Â
lower bound=Â Â âˆš(lower bound variance)= âˆš3066.02 = 55.4
Â Â Â Â Â
Â Â Â Â Â
upper bound=Â Â âˆš(upper bound of variance= âˆš6511.66 = 80.7
Â Â Â Â Â

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