Pure l-phenylalanine has a specific rotation of -35.1 degrees. What is the enantiomeric excess of a...

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Pure l-phenylalanine has a specific rotation of -35.1 degrees.What is the enantiomeric excess of a 10.0 g/mL solution ofphenylalanine which when placed in a standard 1.00 dm cell andanalyzed in a polarimeter rotates plane polarized light -31.6degrees?

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3.6 Ratings (453 Votes)

observed specific rotation = rotation / cell length x concentration

                                        = -31.6 / 1 x 10

                                         = -3.16 oC

enantiomeric excess = observed specific rotation x 100 / pure specific rotation

                                   = -3.16 x 100 / -35.1

                                 = 9.0 %


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