Projectile Motion - Rocket Clears Wall - General Launch Angle A rocket is fired at an initial...

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Physics

Projectile Motion - Rocket Clears Wall - General LaunchAngle
A rocket is fired at an initial speed v0 = 165.0 m/s from groundlevel, at an angle Î¸ = 50Â° above the horizontal.
A wall is located at d = 67.0 m. Its heigh is h = 47.0 m. Ignoreair resistance.
The magnitude of the gravitational acceleration is 9.8 m/s2.
Choose the RIGHT as positive x-direction. Choose UPWARD aspsotitive y-direction
Find v0x, the x component of the initial velocity (in m/s) .Keep 2 decimal places.
Find v0y, the y component of the initial velocity (in m/s) .Keep 2 decimal places.
You will calculate the time at which the rocket flies over thewall.
To find this time, should you use the horizontal (x) motion orthe vertial (y) motion?
(a) At what time (in seconds) (after being fired) does therocket fly over the wall? Keep 4 decimal places.
Note: when the rocket flies over the wall, in general, theheight of the rocket is not equal to the maximum height.
(b) What is the rocket's height (in meters) when it flies overthe wall? Keep 3 decimal places.
(c) By how much (in meters) does the rocket clear the top of thewall? Keep 3 decimal places.
(d) What is the rocket's maximum height (in meters) above theground? Keep 2 decimal places.

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4.2 Ratings (514 Votes)

Given that Rocket is fired at V0 1650 msec at 50 deg abovethe horizontalV0x Initial horizontal velocity V0cos 1650cos 50 deg 10606 msV0y Initial vertical velocity V0sin 1650sin 50 deg 12640 msto find the See Answer

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