Problem Binomial Distribution: A consumeradvocate claims that 80 percent of cable televisionsubscribers are not satisfied with their cable service. Inan attempt to justify this claim, a randomly selected sample ofcable subscribers will be polled on this issue.
Suppose that the advocate’s claim is true, and suppose that arandom sample of 25 cable subscribers is selected.Assuming independence, find:
(2) The probability that more than 20subscribers in the sample are not satisfied with theirservice. Minitab instructions: Go to Calc >select Probability Distributions > select Binomial > selectCumulative probability > Number of Trials insert 25 > EventProbability insert “.8†> Input Constant insert “20.†ClickOK.Paste your Minitab results here and then show your workto calculate P(x > 20) = 1 –P(x ≤ 20) to get your final answer:
(3) The probability that between 20 and 24 (inclusive)subscribers in the sample are not satisfied with theirservice.
(A) Miniab instructions: Go to Calc > selectProbability Distributions > select Binomial > selectCumulative probability > Number of Trials insert 25 > EventProbability insert “.8†> Input Constant insert “19.†ClickOK.
(B) Minitab instructions: Go to Calc >select Probability Distributions > select Binomial > selectCumulative probability > Number of Trials insert 25 > EventProbability insert “.8†> Input Constant insert “24.†Click OK.Paste each of your Minitab results here and then show yourwork to calculate P(20 ≤ x ≤ 24) = P( x≤24) – P(x≤ 19) to get your finalanswer:
(4)Â Â The probability that exactly 24subscribers in the sample are not satisfied with theirservice.Paste your Minitab results here:
c) Suppose that when we survey 25 randomly selected cabletelevision subscribers, we find that 15 are actually notsatisfied with their service. Using a probability youfound in this exercise as the basis for your answer, do you believethe consumer advocate’s claim? Explain your answerhere:
