Problem 1: For the reaction 2CH3OH(l) + 3O2(g) = 2CO2 + 4H2O(l) I calculated that the change...

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Chemistry

Problem 1: For the reaction 2CH₃OH_(l) +3O₂_(g) = 2CO₂ +4H₂O_(l) I calculated that the change in molarentropy of the system is 313.7Joules/(moleskelvin). The question then asked what is the entropychange of the system when 2.35 moles ofO₂ react. I multiplied 313.7 Joules/(moleskelvin) by2.35 moles of O₂ and also divided by 3 moles ofO₂ because of the \"3\" coefficient, and got 246Joules/kelvin and I just want to make sure that last part wascorrect. Specifically, was I correct to both multiply by 2.35 anddivide by 3.
Problem 2: Very similar problem. For the reactionH_2(g) + F_2(g) = 2HF_(g) Icalculated that the change in molar entropy of thesurroundings is 1,819 Joules/(moleskelvin). Thequestion then asked to calculate the entropy change of thesurroundings when 2.15 moles of H_2(g)react, so I multiplied 1,819 Joules/(moleskelvin) by 2.15 moles ofH₂_(g) and then divided by 1 moles ofH_2(g) since the coefficient is \"1\" and got 3,911Joules/kelvin, and I just want to make sure this last part iscorrect. Specifically, was I correct to multiply by 2.15 and thendivide by 1

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Q1According to the 3rd law of thermodynamics entropy change is calculated by substracting the total energy of reactants from the total energy of products The total energy of each reactant and See Answer

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