Predict the products for the following reactions. If no reaction will occur, write NR. Remember to...

3.7 Ratings (422 Votes)

The reactions are Cu+2 (aq)+2e----->Cu Eo=0.337V (1)

Au+ (aq) e-------------->Au , EO=1.68 V

multiplying with 2 and reversing the reaction gives 2 Au----------> 2Au(s) + 2e-Â Â Â Â Â Â Â Â Â Â Â Â Â Eo=-1.68V (2)

addition of 1 and 2 gives Cu+2(aq) + 2Au-(s)--------> Cu(s) Eo= 0.337-0.168 =1.343 V Since

deltaG= -nFE, the reactino is spontaneous

b) The second reaction

becuae Na+ + e-Â Â Â Â Â Â Â Â Â ---------------> Na (s) EO= =2.714 V

Na (s)------------> Na+ +e-Â Â Â Â Â Â Â Â Â Â Â Â Â Eo= 2.714 V

multiplying by 2 gives 2Na ---------> 2Na+ + 2e- Eo= 2.714 V

Ni+2 + 2e-Â Â Â Â Â Â Â Â Â -------------. Ni Eo= -0.25V

when added gives 2Na + Ni+2 ------->2Na+ + Ni Eo= 2.714-0.25= 2.646 V

since deltaG= -nFE is -ve, the reaction is possible.

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