Polarimetry Lab calculations: Isomer Observed Degree of Rotation(Raw data) (+) Carovene 158.75Â° (-) Carovene 229.75Â° Blank 200.75Â° Unknown (X) 175.25Â° I would like some help to...

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Chemistry

Polarimetry Lab calculations:
Isomer
Observed Degree of Rotation(Raw data)
(+) Carovene
158.75Â°
(-) Carovene
229.75Â°
Blank
200.75Â°
Unknown (X)
175.25Â°
I would like some help to figure out how to do this; I want tomake sure that I am doing it correct. Here is what I have done sofar:
Find specific rotations for all the isomers:
I believe these are the equations to use:
X _observed= X _raw -BlankÂ Â Â Â Â Â Â Â Â Â Â Â l= 0.8 dm and c= 0.9600 g/cm³
[X]= X _observed / lc
Can someone show me the calculations for all of them,this is what I did for Unknown:
My Unknown (X): I did x observed= 175.25-200.75=-25.5Â°
**[X]= X _observed / lc -25.5Â°/(0.8*0.9600)=-33.20Â°**
Find the Enantiomer Excess:
The equations our teacher gavewere:
EE= [X] _observed /[X]_pure * 100
([X]_pure can be found by[X]= X_pure/ lc
I donâ€™t know how to find x pure. What even is that,where can I get it from the numbers. After I get EE,
I need to find how much of (-) and (+) is in theenantiomer (the equation given for that is
EE= [X]₊ XA +[X]_- (1-X₊)
[X]₊ and [X]_- aresupposed to be answers from number 1.

Answer & Explanation Solved by verified expert

4.3 Ratings (588 Votes)

Let X is the specific rotation of carovene X observed rotation lc given l 08 dm c 096 g cc lc 08 x 096 0768 X 15875 20075 0768 420768 547 0 similarly X the specific rotation of carovene See Answer

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Isomer	Observed Degree of Rotation(Raw data)
(+) Carovene	158.75Â°
(-) Carovene	229.75Â°
Blank	200.75Â°
Unknown (X)	175.25Â°