Please use sig figs and dimensional analysis and explain process! 1. Dissolve 69.0 g NaNO2 in 1.00...

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Chemistry

Please use sig figs and dimensional analysisand explain process!
1. Dissolve 69.0 g NaNO₂ in 1.00 x 10² mLH₂O.
(a) If the temperature of the solution is 100Â°C, what is thevapor pressure above the solution? The density of H₂O at100Â°C is 0.9591 g/mL.
(b) Calculate the change in the boiling point of the solution,and calculate the boiling point of the aqueous solution.
(c) Calculate the freezing point of the solution. The density ofH₂O at 0Â°C is 0.9998 g/mL.
(d) Which change is greater, the boiling point elevation or thefreezing point depression?
(e) Estimate the osmotic pressure at 25 Â°C for the solution.Assume that dissolved sodium nitrite does not affect the volume ofthe solution.

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4.3 Ratings (709 Votes)

1 Dissolve 690 g NaNO2 in 100 x 102 mL H2O a If the temperature of the solution is 100C what is the vapor pressure above the solution The density of H2O at 100C is 09591 gmL Solution to calculate the vapor pressure above the solution we need to calculate the ole fraction of the solvent Because the formula to calculate the vapor pressure is as follows Vapor pressure of solution mole ffraction of solvent vapor pressure of the pure solvent So lets first calculate the moles of the NaNO2 and moles of water Moles mass molar mass Moles of NaNO2 690 g 689953 g per mol 100 mol NaNO2 Moles of water 9591 g 180148 g See Answer

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