Please provide an aswer and reference(s) to the question below from a classmate. Thank you in advance! Class, I...

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Please provide anaswer and reference(s) to the question below from a classmate.Thank you in advance!

Class,

I am having a problemwith the following problem:

A certain brand ofautomobile tire has a mean life span of 39,000 miles and a standarddeviation of 2,250 miles.​ (Assume the life spans of the tires havea​ bell-shaped distribution.)

For the life span of34,000 miles, z-score is = 34,000 x 39,000 = -2.22

2,250

For the life span of34,000 miles, z-score is = 38,000 x 39,000 = -0.44

2,250

For the life span of34,000 miles, z-score is = 31,000 x 39,000 = -3.56

2,250

The following is thepart I am having trouble with:

The life spans ofthree randomly selected tires are 34,500 miles, 43,500 miles, and39,000

miles. Using theempirical​ rule, find the percentile that corresponds to each lifespan:

1. The life span34,500 miles corresponds to the ___th percentile?

2. The life span43,500 miles corresponds to the ___th percentile?

3. The life span39,000 miles corresponds to the ___th percentile?

I have found in thetext in Chapter 2, p.88 where it talks about Empirical Rules andBell-Shaped Distribution. I did find that number 3 is \"50\"thpercentile, as it is also the mean value in this problem set.Numbers 1 and 2 I am having an issue calculating. Any help from mybattle buddies would be outstanding. Thank you in advance!

Reference:

Larson, R. &Farber, B. (2015). Elementary Statistics: picturing theworld. 6th edition.

Answer & Explanation Solved by verified expert
4.3 Ratings (752 Votes)
The Figure below will helpThe percentile is the percentage of values that lie below acertain specified valueThe emperical rule or the 6895997 rule states that1 About 68 of the values fall within 1 standard deviation ofthe mean ie from Therefore 34 lies to the left ie    See Answer
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