Please explain how to solve and show all work! I'm extremely lost. Part 1: A 180,000 gal. swimming...

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Chemistry

Please explain how to solve and show all work! I'm extremelylost.
Part 1:
A 180,000 gal. swimming pool requires treatment with 8.85 L of7.00% \"by mass\" chlorinating solution to give chlorine level of1.00 ppm (1.00 g chlorine per 10^3 kg of pool water). Based onthese data, calculate d (in g/ml) for the chlorinating solutionnothing that it is close to 1 g/mL. * \"% by mass\" means \"mass ofsolute/100g solution\". thus, this chlorinating solution contains7.00 g chlorine/100 g chlorinating solution.
Part 2:
Take pool water as pure and, for the poo, calculate the H2O/Cl2molecular ration after treatment with the 8.85 L of thechlorinating soln.
Part 3:
If density, d (pool water) = 1.00 g/mL, and d (chlorinatingsolution) = 1.10 g/mL, calculate volume, V, of chlorinatingsolution to add to the 180,000 gal pool water to up d of resultingpool wter to 1.01 g/mL.

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4.1 Ratings (655 Votes)

1 gallon 378 liters 180000 gallons 378 180000 680400 liters 680400103 ml Denisty 1 gmml hence gms of water 680400 X103 gm Final chlorine water contains 1gm of chlorine per 1000 kg water or 1gm chlrorine per 106 gm of water 1gm per 106 gm of water Total See Answer

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