PLEASE ANSWER PARTS A, C, AND D. Thank you! 2.2 For diagnostic testing, let X =...

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PLEASE ANSWER PARTS A, C, AND D. Thank you!

2.2 For diagnostic testing, let X = true status (1 = disease, 2= no disease) and Y = diagnosis (1 = positive, 2 = negative). Let?i = P (Y = 1|X = i), i = 1, 2.

a. Explain why sensitivity = ?1 and specificity = 1 ? ?2.

c. For mammograms for detecting breast cancer, suppose ? = 0.01,sensitivity = 0.86, and specificity = 0.88. Given a positive testresult, find the probability that the woman truly has breastcancer.

d. To better understand the answer in (c), find the jointprobabilities for the 2 × 2 cross-classification of X and Y .Discuss their relative sizes in the two cells that refer to apositive test result.

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ASensitivity is the probability that the diagnostic test ispositive given that a subject has the disease that is PY 1 X 1 so its probability is given by 1Specificity is the    See Answer
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