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Phosphine decomposes by the following reaction: COCl2(g) <---> CO(g) + Cl2(g) Kc = 8.3 x 10-4 Calculate the...

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Chemistry

Phosphine decomposes by the following reaction:

COCl2(g) <---> CO(g) +Cl2(g) Kc = 8.3 x 10-4

Calculate the concentration of each component when 2.55 g ofphosphine decomposes in a 25.0mL flask.

Answer & Explanation Solved by verified expert
4.1 Ratings (841 Votes)

mass of COCl2 = 2.55 g

moles of COCl2 = 2.55 / 98.92 = 0.0258 mol

concentration = 0.0258 / 0.025 = 1.03 M

COCl2 (g)   <------------->   CO (g) +   Cl2 (g)

1.03                                    0              0

1.03 - x                               x                x

Kc = x^2 / 1.03 - x

8.3 x 10-4 = x^2 / 1.03 - x

x = 0.0292

concentration of compounds :

[COCl2] = 1.00 M

[CO] = 0.0292 M

[Cl2] = 0.0292 M
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