Phenotypes to Genotypes- Background: The IAA3 from wild-type Arabidopsis has been sequenced and is included below...

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Biology

Phenotypes to Genotypes- Background: The IAA3 fromwild-type Arabidopsis has been sequenced and is included below asthe top strand in the 5’ to 3’ orientation.

        1 gctgttactgctaccgacaa gcttagcttt ttttcctttg tccttaattc agaaaacagt

       61 ttcttctctctctaccagta tctatcttta ttctccttta acttgtataa aacactcagc

      121 ttcctcgaag cctctcatcttcatcatcag cagcttctct atatctctcc tctctttcaa

      181 ggataataac caaaagcttttctttttatc ttctcctgca attcttgaag aaatggatga

      241 gtttgttaac ctcaaggaaacagagctgag gctgggatta ccgggaacag ataatgtatg

      301 tgaagcaaaa gagagagtttcttgctgtaa taacaacaat aagagagtac tatcaactga

      361 tactgagaag gagattgaatcatcatcaag gaaaactgaa acatcccctc ctcgaaagta

      421 agttaaactc acacaaaagtctctgaatct gtagtggtgg agaattcagt tgattgaccg

      481 tgtttcttcc tttttgcagggctcagattg ttggatggcc accagttaga tcttacagga

      541 agaacaacat tcagagtaagaagaatgaat ctgagcatga gggtcaagga atctatgtga

      601 aagtaagtat ggatggtgcaccatacttga ggaaaataga tctgagttgt tacaaaggat

      661 actcagagtt gcttaaagctttagaagtga tgttcaaatt ctctgtggga gagtactttg

      721 agagagatgg atataaaggttcagactttg tgcctactta tgaagacaaa gatggtgatt

      781 ggatgctcat tggtgatgttccatgggagt aagtcttctt tcatatacct gtctgaaaac

      841 aatttccaca aaatcaaaaatcagaaacaa caattttgta agtgttctta tgggttctgt

      901 ttgttgttgc aggatgttcatatgtacgtg caagagacta aggatcatga aaggatcaga

      961 agccaaaggt ttaggctgtggtgtatgaga tatatcttca agaaatctaa cagagacaca

     1021 aaagaacttg aagaaaaatagagtttcttt tggttcagag aaatctctgt ctgtgcttgg

     1081 gttgtcgggt ttctcgggcaagatctatgt tcattggatt gaatccaatt catagccttt

     1141 atttacctca tcggtaaaattcaaatgtaa acatgcttaa tggtcttaag catatgaaac

     1201 tggaacctaa ttacattttgtttcagaaac agggcaaaag gttgtcctta aatctttggt

     1261 tatgtgtatt acattaattaaagtgttatg aagattgaag agttgttttt atatttgtag

     1321 caattctgtt ttgcgttctcattgatcaaa gagattttca agca

  • Primers have been designed to amplify a specific portion(316 base pairs) of the wild-type gene sequence.

3CF gcaaaagagagagtttcttgctg

3CDR tgcaccatccatacttactttcac

Note: these are in 5’ to 3’ orientation

Question- Locate where the primers will adhere to thesequence and amplify this portion of the gene for identification ingel electrophoresis. Highlight the matching 5’ to 3’ sequencing bychanging it to boldface.

1 gctgttactg ctaccgacaa gcttagcttt ttttcctttg tccttaattcagaaaacagt

       61 ttcttctctctctaccagta tctatcttta ttctccttta acttgtataa aacactcagc

      121 ttcctcgaag cctctcatcttcatcatcag cagcttctct atatctctcc tctctttcaa

      181 ggataataac caaaagcttttctttttatc ttctcctgca attcttgaag aaatggatga

      241 gtttgttaac ctcaaggaaacagagctgag gctgggatta ccgggaacag ataatgtatg

      301 tgaagcaaaa gagagagtttcttgctgtaa taacaacaat aagagagtac tatcaactga

      361 tactgagaag gagattgaatcatcatcaag gaaaactgaa acatcccctc ctcgaaagta

      421 agttaaactc acacaaaagtctctgaatct gtagtggtgg agaattcagt tgattgaccg

      481 tgtttcttcc tttttgcagggctcagattg ttggatggcc accagttaga tcttacagga

      541 agaacaacat tcagagtaagaagaatgaat ctgagcatga gggtcaagga atctatgtga

      601 aagtaagtat ggatggtgcaccatacttga ggaaaataga tctgagttgt tacaaaggat

      661 actcagagtt gcttaaagctttagaagtga tgttcaaatt ctctgtggga gagtactttg

      721 agagagatgg atataaaggttcagactttg tgcctactta tgaagacaaa gatggtgatt

      781 ggatgctcat tggtgatgttccatgggagt aagtcttctt tcatatacct gtctgaaaac

      841 aatttccaca aaatcaaaaatcagaaacaa caattttgta agtgttctta tgggttctgt

      901 ttgttgttgc aggatgttcatatgtacgtg caagagacta aggatcatga aaggatcaga

      961 agccaaaggt ttaggctgtggtgtatgaga tatatcttca agaaatctaa cagagacaca

     1021 aaagaacttg aagaaaaatagagtttcttt tggttcagag aaatctctgt ctgtgcttgg

     1081 gttgtcgggt ttctcgggcaagatctatgt tcattggatt gaatccaatt catagccttt

     1141 atttacctca tcggtaaaattcaaatgtaa acatgcttaa tggtcttaag catatgaaac

     1201 tggaacctaa ttacattttgtttcagaaac agggcaaaag gttgtcctta aatctttggt

     1261 tatgtgtatt acattaattaaagtgttatg aagattgaag agttgttttt atatttgtag

     1321 caattctgtt ttgcgttctcattgatcaaa gagattttca agca

Answer & Explanation Solved by verified expert
3.9 Ratings (388 Votes)
The given sequence has 5 to3 polarity The primers are synthesized to amplify the templateDNA Therefore if template DNA is 5 to 3 direction the polarityof primers will be 3 to 5 and vice versaFor amplification of a gene aprimer pair is synthesized to amplify both strands of DNA henceonly one primer sequence can be found in the given template strandthe other sequence will be found on the complementary DNAsequenceIn the given sequence only oneprimer can be    See Answer
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