Part B A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH. Calculate the...
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Chemistry
Part B
A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH.Calculate the pH after the addition of 13.0 mL of KOH.
Express your answer numerically
Part C
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5)is titrated with 0.500 M HNO3. Calculate the pH after theaddition of 21.0 mL of HNO3.
Express your answer numerically.
Part D
A 52.0-mL volume of 0.35 M CH3COOH(Ka=1.8×10−5) is titrated with 0.40 M NaOH.Calculate the pH after the addition of 25.0 mL of NaOH.
Express your answer numerically.
(I will leave a good rating, thank you)
Part B
A 50.0-mL volume of 0.15 M HBr is titrated with 0.25 M KOH.Calculate the pH after the addition of 13.0 mL of KOH.
Express your answer numerically
Part C
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5)is titrated with 0.500 M HNO3. Calculate the pH after theaddition of 21.0 mL of HNO3.
Express your answer numerically.
Part D
A 52.0-mL volume of 0.35 M CH3COOH(Ka=1.8×10−5) is titrated with 0.40 M NaOH.Calculate the pH after the addition of 25.0 mL of NaOH.
Express your answer numerically.
(I will leave a good rating, thank you)
Answer & Explanation Solved by verified expert
4.5 Ratings (936 Votes)
B Given MHBr 015 M VHBr 50 mL MKOH 025 M VKOH 13 mL molHBr MHBr VHBr molHBr 015 M 50 mL 75 mmol molKOH MKOH VKOH molKOH 025 M 13 mL 325 mmol We have molHBr 75 mmol molKOH 325 mmol 325 mmol of both will react remaining mol of HBr 425 mmol Total volume 630 mL H mol of acid
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