Part A What volume of 0.105 M HClO4 solution is needed to neutralize 46.00 mL of 8.80×10−2...

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Chemistry

Part A

What volume of 0.105 M HClO4 solution is needed to neutralize46.00 mL of 8.80×10−2 M NaOH?

Part B

What volume of 0.124 M HCl is needed to neutralize 2.88 g ofMg(OH)2? Part C If 27.0 mL of AgNO3 is needed to precipitate allthe Cl− ions in a 0.755-mg sample of KCl (forming AgCl), what isthe molarity of the AgNO3 solution?

Part D

If 45.8 mL of 0.118 M HCl solution is needed to neutralize asolution of KOH, how many grams of KOH must be present in thesolution?

Answer & Explanation Solved by verified expert
3.8 Ratings (377 Votes)
Part A Given HClO40105 M NaOH 880E2 M volume of NaOH 4600 mL 0046 L Solution We have to find the volume of HClO4 In order to get its volume we must find its moles by using mole ratio between NaOH and HClO4 Reaction HClO4aq NaOH aq NaClO4 aq H2O l In this reaction we can see the mol ratio between HClO4 and NaOH is 11 We use the volume and molarity    See Answer
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