Part A: Using your graduated cylinder, you calibrate the pipetyou will be using and the values you collect are as follow. What isthe average number of drops per mL of benzene.

  21 dropsdrops   

23 dropsdrops   

  17 dropsdrops   

Part B: After calibration, you use the oleic acid/benzenesolution to form a monolayer. It takes   6dropsdrops   ,   9dropsdrops    and   7dropsdrops    before the layer on the water solutionstarts to make a bubble tha does not go into solution. What is theaverage number of drops for your monolayer?

Part C: Since we have the number of drops it takes to make amonolayer and we have the number of drops it takes to make one mLof benzene, we can determine the mL of oleic acid/benzene it takesto form a monolayer.  

Part D: Next we need to determine the mass of oleic acid in themonolayer. The concentration of the oleic acid/benzene solution is0.02g/L. Calculate how many grams of oleic acid is in one drop.

Part E: With this information, we now need to calculate thevolume in milliliters. We need to know how many mLs a drop of oleicacid occupies using the density of 0.895 g/mL and the number ofdrops of oleic acid solution used. (answer in mL/Drop)

Part F: Determine the volume of the monolayer from the aboveinformation.(in mL)

Part G:Calculate the thinkness of the monolayer assuming thatthe volume of the monolayer is   7.23×10^−6mLmL   and diameter of the watch glass is 5 cm.( answerin cm)

Part H: Determine the number of moles of oleic acid in themonolayer. Assume the nubmer of grams of oleic acid in themonolayer is   7.54×10^−6 (answer in Mol)

Part I: Calculate the surface area of one molecue if we assumethe molecule is shaped like a cylinder that the hight is 10x largerthan the radius.( answer in cm^2)

Part J: Determine the area of the surface covered by themolecues assuming they have a circular surface which at most cancover 90.6%. ( answer in cm^2)

Part K: Calculate the number of molecules in the surface.

Part L: Calculate the number of molecues in 1 mole of calculatedoleic acid.

Part M: Compare this number based on the Avogadro's numberfinding the % error. Discuss why the % error is well over 100% andhow that would be possible.