Part A Escherichia coli (E. coli) can under optimal conditions double every 20.0 minutes. How long would...

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Chemistry

Part A
Escherichia coli (E. coli) can under optimalconditions double every 20.0 minutes. How long would it take asingle cell to saturate a 5.0 L culture assuming that optimalgrowth conditions prevaled and that no cells died? The maximum celldenisty in a saturated culture is 10¹⁰ cellsmL^-1. Enter your answer to the nearest tenth of anhour.
Part B
Consider the information in Part A and decide how long it wouldtake for the 5.0 L culture to attain 1.0% saturation? Again, enteryour answer to the nearest tenth of an hour.
Part C
Imagine that just after the culture described above becamesaturated a researcher poured the culture into 15.0 L of freshgrowth media. How long would it take for this 20.0 L (total volume)cuture to become saturated, again, assuming that optimal conditionsprevailed and that no cells died. Enter your answer to the nearestminute.

Answer & Explanation Solved by verified expert

3.9 Ratings (713 Votes)

First you can construct a table like thistime minNo cells0120240460880161003212064The growth is exponential as you can see in the graph time VsCells so you can make an exponential regression by calculatingthe logarithm See Answer

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